# 2261 k divisible elements

#### Explanation of Finding 2261 Divisible Elements in C++

To find 2261 divisible elements in C++, you can use a loop to iterate through a range of numbers and check if each number is divisible by a specific value. Here is an example of how you can achieve this:

```
#include <iostream>
int main() {
int count = 0;
int divisor = 7; // Change this to the desired divisor
for (int i = 1; count < 2261; i++) {
if (i % divisor == 0) {
std::cout << i << " is divisible by " << divisor << std::endl;
count++;
}
}
return 0;
}
```

Explanation of the code:
1. We start by initializing a variable `count`

to keep track of the number of divisible elements found. We set it to 0 initially.
2. We define a variable `divisor`

to specify the number by which we want to check divisibility. You can change this value to any desired divisor.
3. We use a `for`

loop to iterate through a range of numbers. The loop continues until `count`

reaches 2261, indicating that we have found the desired number of divisible elements.
4. Inside the loop, we use the modulo operator `%`

to check if `i`

is divisible by `divisor`

. If the remainder is 0, it means `i`

is divisible by `divisor`

.
5. If `i`

is divisible by `divisor`

, we print the number and increment `count`

by 1.
6. Once we have found 2261 divisible elements, the loop terminates, and the program exits.

Please note that the code provided is a basic example to demonstrate the concept of finding divisible elements. You can modify it according to your specific requirements.