2261 k divisible elements

Explanation of Finding 2261 Divisible Elements in C++

To find 2261 divisible elements in C++, you can use a loop to iterate through a range of numbers and check if each number is divisible by a specific value. Here is an example of how you can achieve this:

#include <iostream>

int main() {
    int count = 0;
    int divisor = 7; // Change this to the desired divisor

    for (int i = 1; count < 2261; i++) {
        if (i % divisor == 0) {
            std::cout << i << " is divisible by " << divisor << std::endl;

    return 0;

Explanation of the code: 1. We start by initializing a variable count to keep track of the number of divisible elements found. We set it to 0 initially. 2. We define a variable divisor to specify the number by which we want to check divisibility. You can change this value to any desired divisor. 3. We use a for loop to iterate through a range of numbers. The loop continues until count reaches 2261, indicating that we have found the desired number of divisible elements. 4. Inside the loop, we use the modulo operator % to check if i is divisible by divisor. If the remainder is 0, it means i is divisible by divisor. 5. If i is divisible by divisor, we print the number and increment count by 1. 6. Once we have found 2261 divisible elements, the loop terminates, and the program exits.

Please note that the code provided is a basic example to demonstrate the concept of finding divisible elements. You can modify it according to your specific requirements.