# drop haskell

In Haskell, the `drop`

function is used to remove a specified number of elements from the beginning of a list and return the remaining elements. The `drop`

function takes two arguments: the number of elements to drop and the list from which to drop the elements.

Here's the syntax for the `drop`

function:

```
drop :: Int -> [a] -> [a]
```

The first argument is of type `Int`

and represents the number of elements to drop. The second argument is of type `[a]`

, which denotes a list of elements of any type `a`

. The `drop`

function returns a new list `[a]`

that contains the remaining elements after dropping the specified number of elements from the beginning.

Here's an example usage of the `drop`

function:

```
drop 3 [1, 2, 3, 4, 5] -- returns [4, 5]
```

In this example, the `drop`

function is called with the arguments `3`

and `[1, 2, 3, 4, 5]`

. It drops the first three elements from the list and returns `[4, 5]`

.

Note that if the specified number of elements to drop is greater than the length of the list, an empty list `[]`

is returned.

I hope this clarifies the usage of the `drop`

function in Haskell!