fibnocci code in haskell language

Sure! Here's a Fibonacci code in Haskell:

fib :: Int -> Int
fib 0 = 0
fib 1 = 1
fib n = fib (n-1) + fib (n-2)

This code defines a function fib that takes an Int parameter n and returns the nth Fibonacci number. The Fibonacci sequence starts with 0 and 1, and each subsequent number is the sum of the previous two numbers.

The function uses pattern matching to handle the base cases where n is 0 or 1. For any other value of n, it recursively calls fib on n-1 and n-2 and adds the results together.

You can call this function with an integer argument to calculate the corresponding Fibonacci number. For example, fib 5 would return 5, as the 5th Fibonacci number is 5.

I hope this helps! Let me know if you have any further questions.